Calculate the number of atoms present in 1.625 g metal if it forms bcc unit cell structure. [ a^3 = 3.25 10⁻²² g ]

Step-by-step solution

Mass of one unit cell is given by a^3 = 3.25 10⁻²² g. For a body-centered cubic (bcc) structure, the number of atoms per unit cell is Z = 2 . Mass of one atom = Mass of unit cell Z = 3.25 10⁻²² 2 = 1.625 10⁻²² g. Total number of atoms in 1.625 g of the metal = Total mass Mass of one atom Number of atoms = 1.625 1.625 10⁻²² = 1.0 10²² Answer: 1.0 10²²