MHT CET202611 April 2026Morning ShiftChemistrySolid StateActual
Pt has FCC structure with an edge length of unit cell 392 pm. What is the radius of Pt?
Options
- A138.6 pm
- B175.6 pm
- C185.6 pm
- D205.6 pm
Correct answer
A. 138.6 pm
Step-by-step solution
For an FCC (face-centered cubic) structure, the relationship between the edge length a and the atomic radius r is given by: 4r = 2 a r = a 2 2 Given a = 392 pm: r = 392 2 2 = 196 2 r = 98 2 Using 2 1.414 : r = 98 1.414 = 138.57 pm 138.6 pm Answer: 138.6 pm