MHT CET202520 Apr 2025Evening ShiftChemistrySolid StateActual
Calculate the volume occupied by a particle in bcc unit cell if the volume of unit cell is 8.2 10⁻²³ ~cm ^3
Options
- A5.576 10⁻²³ ~cm ^3
- B1.517 10⁻²³ ~cm ^3
- C2.788 10⁻²³ ~cm ^3
- D3.936 10⁻²³ ~cm ^3
Correct answer
C. 2.788 10⁻²³ ~cm ^3
Step-by-step solution
Volume occupied by a single atom in a BCC unit cell Given the unit cell volume V_ unit cell = 8.2 10⁻²³ cm ^3 , and since the BCC structure contains Z = 2 atoms per unit cell with packing efficiency PE = 0.68 , the volume per atom is derived from the relation: V_ atom = PE V_ unit cell Z Substituting the values: V_ atom = 0.68 8.2 10⁻²³ 2 = 2.788 10⁻²³ cm ^3 The result corresponds to option C .