At 300 ~K , _ r G ^ for the reaction A ₂( ~g ) B ₂( ~g ) is -11.5 kJ mol ⁻¹ . The equilibrium constant at 300 K is approximately ( R =8.314 ~J ~mol ⁻¹ ~K ⁻¹ )

Step-by-step solution

We know that, _ r G ^0=- RT ~K _ eq given, aligned & _ r G ^0=-11.5 ~kJ ~mol ⁻¹ & ~T =300 ~K & R =8.314 ~J ~mol ⁻¹ ~K ⁻¹ & -11.5 10^3 ~J ~mol ⁻¹ & =-8.314 ~J ~mol ⁻¹ ~K ⁻¹ 300 ~K K _ eq aligned or, 4.6106=2.303 ₁₀ ~K _ eq aligned & ₁₀ ~K _ eq =2 & ~K _ eq =(10)^2 & ~K _ eq =100 aligned