Calculate the number of atoms in 20 gram metal which crystalises to simple cubic structure having unit cell length 340 pm . (density of metal =9.8 ~g ~cm ⁻³ )

Step-by-step solution

d = Z M V N _ A 9.8= 1 M (3.40 10⁻⁸ )^3 6.02 10²³ aligned & M= 9.8 6.02 39.3 10 & =231.87 aligned Moles of atom in 20 ~g sample = 20 231.87 =0.08625 No. of atoms =0.08625 6.02 10²³=5.19 10²²