How many number of unit cells are present in 100 ~g of an element with fcc crystal having density 10 ~g / cm ³ and edge length 100 pm ?

Step-by-step solution

aligned Vol. of unit cell &=(100 pm )³= (100 10⁻¹⁰ ~cm )³ &=10⁻²⁴ ~cm ³ aligned Vol. of 100 ~g of an element = Mass Density = 100 ~g 10 ~g ~cm ⁻³ =10 ~cm ³ No. of unit cells in 100 ~g of an element = Total volume Volume of one unit cell = 10 ~cm ³ 10⁻²⁴ ~cm ³ =1 10²⁵ unit cells.