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AP EAMCET20227 Jul 2022Evening ShiftChemistryThermodynamics (C)Actual

The standard Gibb's energy ( G^ ) for the following reaction is aligned & A(s)+B²⁺(a q) A²⁺(a q)+B(s), & K_C=10¹² at 25^ C (K_C= equilibrium constant ) aligned

Options

  1. A-150 ~kJ
  2. B-96.80 ~kJ
  3. C-68.47 ~kJ
  4. D-100 ~kJ

Correct answer

C. -68.47 ~kJ

Step-by-step solution

The standard Gibb's free energy change ( G^ ) at standard conditions is given by the formula G^ =-R T K_ eq where, R is gas constant =8.314 ~J ~mol ⁻¹ ~K ⁻¹ , T=(25+273) K =298 ~K and K_ eq is the equilibrium constant aligned G^ & =-8.314 298 2.303 10¹² & =-68,47018 ~J =-68.47 ~kJ aligned

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