AP EAMCET202119 Aug 2021Evening ShiftChemistryThermodynamics (C)Actual
Two flasks A and B have equal volumes. A is maintained at 300 K and B at 600 K . Equal masses of H 2 and CO 2 are taken in flasks A and B respectively. Find the ratio of total K . E of gases in flask A to that of B .
Options
- A1 : 2
- B11 : 1
- C33 : 2
- D55 : 7
Correct answer
B. 11 : 1
Step-by-step solution
We know that the average kinetic energy depends on the temperature and number of moles. Now, K . E . expression for flasks   A and B is given below: K . E . A ​ = 3 n A RT   A ​ ​ 2 K . E . B = 3 n B RT B 2 Assume common mass = m n A = m / 2 n B ​ = m / 44 K . E . A K . E . B = n A T A n B T B = m / 2 × 300 m / 44 × 600 = 11 : 1