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MHT CET202619 April 2026Evening ShiftChemistryThermodynamics (C)Actual

Calculate standard Gibbs energy for any gaseous reaction if values of K_p and R respectively are 3.5 10¹⁷ ; 8.314 , JK ⁻¹ mol ⁻¹

Options

  1. A-100.1 , kJ mol ⁻¹
  2. B-79.5 , kJ mol ⁻¹
  3. C-71.4 , kJ mol ⁻¹
  4. D-89.5 , kJ mol ⁻¹

Correct answer

A. -100.1 , kJ mol ⁻¹

Step-by-step solution

The standard Gibbs free energy change is given by the relation: G^ = -RT K_p = -2.303 RT K_p Assuming standard temperature T = 298 , K : G^ = -2.303 8.314 298 (3.5 10¹⁷) G^ = -5705.8 ( 3.5 + 17) G^ = -5705.8 (0.544 + 17) G^ = -5705.8 17.544 G^ = -100102 , J mol ⁻¹ -100.1 , kJ mol ⁻¹ Answer: -100.1 , kJ mol ⁻¹

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