MHT CET202619 April 2026Morning ShiftChemistryThermodynamics (C)Actual
An ideal gas expands from initial volume 5 dm ^3 to 15 dm ^3 against a constant external pressure of 2 atm. What is the work done by the gas ?
Options
- A-1202.6 J
- B-2026.4 J
- C-1101.32 J
- D-1013.2 J
Correct answer
B. -2026.4 J
Step-by-step solution
The work done by a gas during expansion against a constant external pressure is given by the formula: W = -P_ ext V Given: P_ ext = 2 atm V_i = 5 dm ^3 = 5 L V_f = 15 dm ^3 = 15 L Change in volume: V = V_f - V_i = 15 - 5 = 10 L Substituting the values into the formula: W = -2 atm 10 L = -20 L atm To convert the work done into Joules, use the conversion factor 1 L atm = 101.32 J : W = -20 101.32 J = -2026.4 J Answer: -2026.4 J