What is the nature of reaction at 298 K , if the entropy change and enthalpy change for a chemical reaction are 7 . 4 cal K - 1 and - 2 . 5 × 10 3 cal , respectively.

Step-by-step solution

As Gibbs free energy tells us about the spontenity of the reaction which is calculated as: ∆ G = ∆ H - T ∆ S ∆ G = ( - 2 . 5 × 10 3 )   -   298 × 7 . 4 ∆ G = - 4705 . 2   cal As, Gibbs free energy is negative. So, reaction is spontaneous.