MHT CET202617 April 2026Evening ShiftChemistryThermodynamics (C)Actual
Calculate the standard enthalpy of combustion of carbon monoxide if _f H^ ( CO ) = -110 kJ mol ⁻¹ _f H^ ( CO ₂) = -393 kJ mol ⁻¹
Options
- A-503 kJ mol ⁻¹
- B-110 kJ mol ⁻¹
- C-283 kJ mol ⁻¹
- D-383 kJ mol ⁻¹
Correct answer
C. -283 kJ mol ⁻¹
Step-by-step solution
The combustion reaction of carbon monoxide is given by: CO(g) + 1 2 O ₂ (g) CO ₂ (g) The standard enthalpy of combustion is calculated using the standard enthalpies of formation: _c H^ ( CO ) = _f H^ ( products ) - _f H^ ( reactants ) _c H^ ( CO ) = _f H^ ( CO ₂) - [ _f H^ ( CO ) + 1 2 _f H^ ( O ₂) ] Since the standard enthalpy of formation of O ₂ in its standard state is zero: _c H^ ( CO ) = -393 - (-110 + 0) _c H^ ( CO ) = -393 + 110 = -283 kJ mol ⁻¹ Answer: -283 kJ mol ⁻¹