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MHT CET202616 April 2026Evening ShiftChemistryThermodynamics (C)Actual

Calculate the enthalpy change when 6 g. CO(g) reacts with sufficient NO ₂ (g) according to the following reaction 4 , CO(g) + 2 , NO ₂ (g) 4 , CO ₂ (g) + 2 N ₂ (g) ,; _r H^0 = -1200 kJ

Options

  1. A-16.08 kJ .
  2. B-32.15 kJ .
  3. C-64.29 kJ
  4. D-128.58 kJ .

Correct answer

C. -64.29 kJ

Step-by-step solution

Molar mass of CO = 12 + 16 = 28 g mol ⁻¹ Number of moles of CO = 6 28 = 3 14 mol From the given balanced equation, the enthalpy change for the reaction of 4 mol of CO is -1200 kJ . Enthalpy change for 1 mol of CO = -1200 4 = -300 kJ Enthalpy change for 3 14 mol of CO = -300 3 14 = -64.285 kJ -64.29 kJ Answer: -64.29 kJ

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