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AP EAMCET201920 Apr 2019Evening ShiftChemistryThermodynamics (C)Actual

At 300 ~K , the equilibrium constant for a reaction is 10 . The standard free energy change (in kJ mol ⁻¹ ) for the reaction is

Options

  1. A-57.4
  2. B-115.2
  3. C+57.4
  4. D-57.4

Correct answer

D. -57.4

Step-by-step solution

From Gibbs free energy equation, G=-2.303 R T K Given, K=10, T=300 ~K aligned & R=8.314 ~J / K / mol & G=-2.303 8.314 ~J / mol / K 300 ~K 10 & G=-2.303 8.314 ~J / mol / K 300 ~K & [ 10=1] & G=-5744.14 ~J / mol , G=-5.74 ~kJ / mol aligned Thus, option (d) is correct.

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