At the temperature T ( K ) for the reaction X 2 O 4 l → 2 XO 2 g ΔU = x kJ mol - 1 ΔS = y JK - 1 mol - 1 . Gibbs energy change for the reaction is ( Assume X 2 O 4 , XO 2 are ideal gases )

Step-by-step solution

∆ G   =   ∆ H   - T ∆ S ∆ H   =   ∆ U   + ∆ n g RT ∆ G   = ∆ U   + ∆ n g RT - T ∆ S   ∆ G   = 1000 x   + 2 RT - Ty ∆ G   = 1000 x   + T ( 2 R - y ) ..