Calculate the work done in joule if 1 mole of an ideal gas compressed from volume 24 dm ^3 to 13 dm ^3 at constant external pressure 3 bar.

Step-by-step solution

The work done by a gas during a constant external pressure process is given by W = -P_ ext V , where V = V₂ - V₁ . Given V₁ = 24~ dm ^3 , V₂ = 13~ dm ^3 , and P_ ext = 3~ bar , the volume change is V = 13 - 24 = -11~ dm ^3 . Converting to SI units: 1~ dm ^3 = 10⁻³~ m ^3 and 1~ bar = 10^5~ Pa , yielding P_ ext = 3 10^5~ Pa and V = -11 10⁻³~ m ^3 . Substituting into the work formula: W = -(3 10^5) (-11 10⁻³) = 3300~ J . The calculated work of 3300~ J corresponds to option A.