Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
MHT CET202410 May 2024Morning ShiftChemistryThermodynamics (C)Actual

2 moles of an ideal gas are expanded isothermally and reversibly from 20 L to 40 L at 300 K . Calculate work done. ( R =8.314 ~J ~K ⁻¹ ~mol ⁻¹ )

Options

  1. A-5.713 ~J
  2. B-11.526 J
  3. C-16.939 ~J
  4. D-3457 97 ~J

Correct answer

D. -3457 97 ~J

Step-by-step solution

Given: - n=2 ~mol , - R=8.314 ~J ~K ⁻¹ ~mol ⁻¹ , - T=300 ~K , - V₁=20 ~L , - V₂=40 ~L . Formula for Work Done: W=-2.303 n R T ₁₀ ( V₂ V₁ ) Substitute the values: W=-2.303 2 8.314 300 ₁₀ ( 40 20 ) Simplify the logarithmic term: ₁₀ ( 40 20 )= ₁₀(2) 0.3010 Calculate: gathered W=-2.303 2 8.314 300 0.3010 W=-2.303 4988.4 0.3010 -3457.97 ~J gathered Answer: W=-3457.97 ~J , closest to Option 4: -3,457.97 J.

Practice Thermodynamics (C) on Quantrex Academy →

More from Thermodynamics (C)

Identify the INCORRECT statement 2026The standard enthalpies of formation of CH₄ (g), CO₂ (g) and H₂ O(l) are -74.8 kJ mol ⁻¹ , -393.5 kJ mol ⁻¹ and -285.8 kJ mol ⁻¹ respectively. Then the enthalpy change for the give 2026For an ideal gas undergoing an isothermal change, there is 2026Ozone is formed by the reaction O _ 2(g) + O _ (g) O _ 3(g) , H = -107.2 kJ . Given O=O bond energy is 498.0 kJ mol ⁻¹ , the average bond energy of ozone is: 2026H and S for a reaction are 35.5 kJ mol ⁻¹ and 83.6 J K ⁻¹ respectively. Assuming that H and S do not vary with temperature, the reaction is spontaneous when: 2026The heat of combustion of carbon to CO ₂ is -393.5 kJ mol ⁻¹ . The heat released on the formation of 35.2 g of CO ₂ by combustion of C is: 20265 moles of a gas is allowed to pass through a series of changes as shown in the graph, in a cyclic process. The processes C A , B C and A B respectively are 20251 mole of an ideal gas is allowed to expand isothermally and reversibly from 1 L to 5 L at 300 K. The change in enthalpy (in kJ ) is ( R =8.3 ~J ~K ⁻¹ ~mol ⁻¹ ) 2025 Full Thermodynamics (C) list All MHT CET PYQs