Calculate enthalpy change for following reaction. H ₂ C = CH _ 2( ~g ) + H _ 2( ~g ) H ₃ C - CH _ 3( ~g ) [The bond energy of C - H , C - C , C = C and H - H is 414,347,615 and 435 kJ respectively]

Step-by-step solution

For the reaction, aligned & H ₂ C = CH _ 2( ~g ) + H _ 2( ~g ) H ₃ C - CH _ 3( ~g ) & _ r H ^ = H _ reactant ^ - H _ product ^ & = [4 H _ ( C - H ) ^ + H _ ( C=C ) ^ + H _ ( H - H ) ^ ] & - [6 H _ ( C - H ) ^ + H _ ( C - C ) ^ ] & =[(4 414 ~kJ )+615 ~kJ +435 ~kJ ]-[(6 414 ~kJ ) & +347 ~kJ ] & =(1656 ~kJ +615 ~kJ +435 ~kJ )-(2484 ~kJ +347 ~kJ ) & =2706 ~kJ -2831 ~kJ =-125 ~kJ aligned