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MHT CET202210 Aug 2022Evening ShiftChemistryThermodynamics (C)Actual

Mark out the enthalpy of formation of carbon monoxide ( CO ) . Given, C s + O 2 g → CO 2 g ,   ∆ H = - 393.3 kJ / mol and CO g + 1 2 O 2 g → CO 2 g ;   ΔH = - 282 .2  kJ / mol .

Options

  1. A- 111.1 KJ mol -1
  2. B676.1 KJ mol -1
  3. C- 282.8 KJ mol -1
  4. D300.0 KJ mol -1

Correct answer

A. - 111.1 KJ mol -1

Step-by-step solution

To find: C s + 1 2 O 2 g   →   CO g = 0 ;         Δ H f ∘ = ? ?                 ( I ) Given: C s + O 2 g → CO 2 g ;           Δ H f ∘ 1 = - 393 . 3   kJ / mol               II CO s + 1 2 O 2 g → CO 2 g   ;       Δ H f ∘ 2 = - 282 . 2   kJ / mol             III Equation (I) can b

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