MHT CET20228 Aug 2022Evening ShiftChemistryThermodynamics (C)Actual
Calculate bond enthalpy of H - Cl bond from following reaction. H ₂(g)+ Cl ₂(g) 2 HCl (g), _ r H ^ =-185 ~kJ (Given bond enthalpies of H - H , Cl - Cl bonds are 435.0 ~kJ ~mol ⁻¹ and 244 ~kJ ~mol ⁻¹ respectively)
Options
- A340 kJ
- B432 kJ
- C370 kJ
- D864 kJ
Correct answer
B. 432 kJ
Step-by-step solution
aligned & H _ r ^ = ( B E )_ in -( B E )_ out . & H _ r ^ = B E _ H - H + B E _ Cl - Cl -2 B E _ H - Cl & -185=435+244-2 x & 2 x=435+244+185 & x=432 KJ aligned