For the combustion of 1 mole of liquid benzene at 298 ~K , the heat of reaction at constant pressure is -3268 ~kJ ~mol ⁻¹ , what is heat of combustion at constant volume? ( R =8 314 10⁻³ ~kJ ~K ⁻¹ ~mol ⁻¹ .

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Correct answer: A. -3264 2 ~kJ ~mol ⁻¹

array l C ₆ H _ b ( ) + 15 2 O _ 2( ~g ) 6 CO _ 2( ~g ) +3 H ₂ O _ ( ) Q _ p =-3268 ~kJ ~mol ⁻¹, n _ ( g ) =-1.5 ~T =298 ~K , R =8.314 10⁻³ ~kJ ~K ⁻¹ ~mol ⁻¹, Q _ v =? array Now, aligned Q _ p &= Q _ v + n RT Q _ v &= Q _ p - n RT &=-3268- [(-1.5) 8.314 10⁻³ 298 ] &=-3268+3.716 Q _ v &=-3264.284 ~kJ ~mol ⁻¹ aligned

For the combustion of 1 mole of liquid benzene at 298 ~K , the heat of reaction at constant pressure is -3268 ~kJ ~mol ⁻¹ , what is heat of combustion at constant volume? ( R =8 314 10⁻³ ~kJ ~K ⁻¹ ~mol ⁻¹ .

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