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MHT CET2019Morning ShiftChemistryThermodynamics (C)Actual

A gas performs 0.320 kJ work on surrounding and absorbs 120 J of heat from the surrounding. Hence, change in internal energy is

Options

  1. A200 J
  2. B120.32 J
  3. C-200 J
  4. D440 J

Correct answer

C. -200 J

Step-by-step solution

According to first law of thermodynamics, Δ U = q + W Since, work is does on the surrounding. So, W = - 0.320 K J = - 320 J q = 120 J ∴ Δ U = - 320 + 120 = - 200 J

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