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MHT CET2017ChemistryThermodynamics (C)

The work done during combustion of 9 × 10 - 2 k g of ethane, C 2 H 6 (g) at 300 K is (Given R = 8.314 J K − 1 m o l − 1 , atomic mass C = 12 , H = 1 )

Options

  1. A6.236   k J
  2. B-6.236   k J
  3. C18.71 k J
  4. D-18.71   k J

Correct answer

C. 18.71 k J

Step-by-step solution

Work done in chemical reaction is W = - Δ n g R T C 2 H 6 g + 7 2 O 2 g → 2 C O 2 g + 3 H 2 O l ∆ n = 2 - 4.5 = - 2.5 W = - (- 2.5 × 8.314 × 300) = 6.2355 k J/mole For 30 g = 1 m o l e = 6.2355 k J. For 90 g = 3 m o l e s = 18.71 k J.

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