Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
MHT CET202526 Apr 2025Evening ShiftMathematicsEllipseActual

The tangent to the ellipse 9 x^2+16 y^2=288 making equal intercepts on the co-ordinate axes intersects the X -axis and the Y -axis in the points A and B respectively. Then A( O A B)= (where O is origin)

Options

  1. A25 2 sq. units
  2. B25 sq. units
  3. C25 5 2 sq. units
  4. D25 5 sq. units

Correct answer

B. 25 sq. units

Step-by-step solution

A line tangent to the ellipse x^2 32 + y^2 18 = 1 and making equal intercepts on the coordinate axes has equation x + y = k , where k is the intercept length. The condition for tangency c^2 = a^2m^2 + b^2 gives k^2 = (32)(-1)^2 + 18 = 50 . The triangle OAB is formed by the line with intercept k intersecting the axes at A(k, 0) and B(0, k) , and the origin O(0, 0) . The area is given by 1 2 |k| |k| = 1 2 k^2 = 1 2 50 = 25 square units.

Practice Ellipse on Quantrex Academy →

More from Ellipse

The foci of a hyperbola are the same as those of the ellipse with equation 9x^2 + 16y^2 = 144 . If the length of the transverse axis of this hyperbola is 2 , then its equation is: 2026If the two ends of the major axis of an ellipse are (5, 0) and (-5, 0) and one focus lies on the line 3x - 5y - 9 = 0 , then its equation is 2026The length of the latus rectum of the curve represented by x = 3( t + t) and y = 4( t - t) is: 2026If P be any point on the ellipse 16x^2 + 25y^2 = 400 with foci S and S' and area of PSS' is 9 square units, then the abscissa of point P is........... 2026If is the eccentric angle of a point on the ellipse x^2 25 + y^2 9 = 1 such that the distance of the point from the center is 5 , then = ....... 2026The eccentricity of the ellipse represented by the equation 7x^2 + 16y^2 - 14x + 64y - 377 = 0 is... 2026A tangent having slope - 1 2 to the ellipse 3x^2 + 4y^2 = 12 intersects the X-axis and Y-axis at the points A and B respectively. if O is the origin, then the area of AOB is ... 2026If the eccentricity of the ellipse x^2 a^2 + y^2 b^2 = 1, (a > b) is 2 3 and its focal chord is 3x + 2y - 6 = 0 , then the value of a^2 + b^2 is... 2026 Full Ellipse list All MHT CET PYQs