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MHT CET202613 April 2026Evening ShiftPhysicsCenter of Mass, Momentum and CollisionActual

100 balls each of mass m moving with speed v simultaneously strike a wall normally and reflected back with same speed, in time t s. The total magnitude of force exerted by the balls on the wall is

Options

  1. A100mv/t
  2. B200mv/t
  3. C200mvt
  4. Dmv/100t

Correct answer

B. 200mv/t

Step-by-step solution

Initial momentum of one ball is p_i = mv . Final momentum of one ball after reflection is p_f = -mv . Change in momentum of one ball is p = p_f - p_i = -mv - mv = -2mv . Magnitude of change in momentum for one ball is 2mv . Total change in momentum for 100 balls is 100 2mv = 200mv . The total magnitude of force exerted on the wall is the rate of change of momentum, given by F = p_ total t = 200mv t .

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