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MHT CET202519 Apr 2025Morning ShiftPhysicsCenter of Mass, Momentum and CollisionActual

There is head-on elastic collision between the two particles moving in the same direction with speeds 5 ~m / s and 3 ~m / s respectively. After collision, the velocity of the first particle becomes 4 ~m / s in the same direction. The velocity of the second particle should be

Options

  1. A6 ~m / s in the same direction.
  2. B4 ~m / s in the same direction.
  3. C2 ~m / s in the opposite direction.
  4. D3 ~m / s in the same direction.

Correct answer

A. 6 ~m / s in the same direction.

Step-by-step solution

Given the initial velocities u₁ = +5 ; m/s and u₂ = +3 ; m/s , and the final velocity of the first particle v₁ = +4 ; m/s , the velocity of the second particle after an elastic collision is determined using the relation for relative velocities: u₁ - u₂ = v₂ - v₁ . Substituting the known values: 5 - 3 = v₂ - 4 , which simplifies to 2 = v₂ - 4 . Solving for v₂ yields v₂ = 6 ; m/s , indicating motion in the positive (initial) direction. The velocity of the second particle is thus 6 ; m/s .

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