MHT CET202415 May 2024Evening ShiftPhysicsCenter of Mass, Momentum and CollisionActual
1000 small balls, each weighing 1 gram, strike one square cm of area per second with a velocity 50 ~m / s in a normal direction and rebound with the same velocity. The value of pressure on the surface will be
Options
- A10^7 ~N / m ^2
- B10^6 ~N / m ^2
- C5 10^6 ~N / m ^2
- D2 10^6 ~N / m ^2
Correct answer
B. 10^6 ~N / m ^2
Step-by-step solution
Given that, aligned & N =10^3, ~m =1 ~g =10⁻³ ~kg , & ~A =1 ~cm ^2=10⁻⁴ ~m ^2, v =50 ~m / s aligned Change in momentum in each collision = m [ v -(- v )]=2 mv Force exerted on the surface aligned & =10^3 2 mv & =10^3 2 10⁻³ 50=100 ~N aligned Now, Pressure = F A = 100 10⁻⁴ =10^6 ~N / m ^2 .