MHT CET202312 May 2023Morning ShiftPhysicsCenter of Mass, Momentum and CollisionActual
A particle of mass ' m ' moving east ward with a speed ' v ' collides with another particle of same mass moving north-ward with same speed ' v '. The two particles coalesce after collision. The new particle of mass ' 2 ~m ' will move in north east direction with a speed (in m / s )
Options
- AV
- B2 ~V
- CV 2
- DV 2
Correct answer
D. V 2
Step-by-step solution
Momentum of particle moving towards east p ₁ = mv i Momentum of particle moving towards North p₂ =m v j Momentum after collision, p =2 m (v_x i +v_y j ) Applying momentum conservation, array ll & p₁ + p₂ = p & m v i +m v j =2 m (v_x i +v_y j ) & 2 m v_x=m v & v_x= v 2 array Similarly, v _ y = v 2 v _ R = v _ x ^2+ v _ y ^2 = ( v 2 )^2+ ( v 2 )^2 = v 2