A body of mass 'm' moving with speed 3 ~m / s collides with a body of mass ⁴ 2 ~m ^ at rest. The coalesced mass will start to move with a speed of

Step-by-step solution

Initial velocity of moving mass u ₁=3 ~km / h Initial velocity of stationary mass u ₂=0 Thus momentum of the system initially P_ i =m₁ u₁+m₂ u₂ P_ i =3 m+0=3 m Let the velocity of coalesced mass be V. Thus momentum of the system finally P _ f = ( m ₁+ m ₂ ) V =3 mV Using conservation of linear momentum P_ i =P_ f 3 ~m =3 ~mV V =1 ~km / h