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MHT CET202019 Oct 2020Evening ShiftPhysicsCenter of Mass, Momentum and CollisionActual

In a system of two particles of masses 'mi' and 'm2', the first particle is moved by a distance 'd' towards the centre of mass. To keep the centre of mass unchanged, the second particle will have to be moved by a distance

Options

  1. Am ₁ ~m ₂ ~d , towards the centre of mass.
  2. Bm ₂ ~m ₁ ~d , away from the centre of mass.
  3. Cm ₂ ~m ₁ ~d , towards the centre of mass.
  4. Dm ₁ ~m ₂ ~d , away from the centre of mass.

Correct answer

A. m ₁ ~m ₂ ~d , towards the centre of mass.

Step-by-step solution

the 2 masses are miand m2 let x and y be the distance of miand m 2 from the centre of mass respectively... now, m₁ x=m₂ y the mass m 1 is moved by a distance d , let the mass m 2 be moved by a distance D therefore, m₁(x-d)=m₂(y-D) m ₁ x - m ₁ ~d = m ₂ y - m ₂ D by eqn (i) m₁ x=m₂ y=>- m ₁ ~d =- m ₂ D = D = m ₁ ~d ~m 2

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