MHT CET202016 Oct 2020Morning ShiftPhysicsCenter of Mass, Momentum and CollisionActual
A bullet of mass m moving with velocity 'v' is fired into a wooden block of mass 'M'. If the bullet remains embedded in the block, the final velocity of the system is
Options
- AV m(M+m)
- Bm+M m
- CM + m mV
- DmV m + M
Correct answer
D. mV m + M
Step-by-step solution
Since there is no extra force other than the action and reaction force so the linear momentum should be conserved. Suppose the system moves with velocity V then momentum before collision is mv and that after collision will be (M+ m ) V Equating both we get m v=(M+m) V or V= m m+M ^ v