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MHT CET202613 April 2026Evening ShiftPhysicsDual Nature of MatterActual

An electron accelerated through a potential difference V₁ has a de-Broglie wavelength of . When the potential is changed to V₂ , its de-Broglie wavelength increases to 2 . The value of (V₁/V₂) is equal to

Options

  1. A3:1
  2. B9:4
  3. C3:2
  4. D4:1

Correct answer

D. 4:1

Step-by-step solution

The de-Broglie wavelength of an electron accelerated through a potential difference V is given by = h 2meV . This implies 1 V , or V 1 ^2 . For the first case, V₁ 1 ^2 . For the second case, V₂ 1 (2 )^2 = 1 4 ^2 . Taking the ratio of the two potentials: V₁ V₂ = 1 ^2 1 4 ^2 = 4 Thus, V₁ V₂ = 4:1 . Answer: 4:1

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