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MHT CET202526 Apr 2025Evening ShiftPhysicsDual Nature of MatterActual

The graph shows the variation of photocurrent with anode potential for four different radiations. Let I_a, I_b, I_c and I_d are intensities and f_a, f_b, f_c and f_d be the frequencies for the curves a, b, c and d respectively, then

Options

  1. Af _ b > f _ a , f _ b = f _ c , I _ c = I _ d
  2. Bf _ b = f _ a , f _ b > f _ c , I _ c > I _ d
  3. Cf _ b < f _ a , f _ b < f _ c , I _ c < I _ d
  4. Df _ b f _ a , f _ b > f _ c , I _ c = I _ d

Correct answer

A. f _ b > f _ a , f _ b = f _ c , I _ c = I _ d

Step-by-step solution

The photocurrent versus anode potential graph for different radiation sources is analyzed using key photoelectric principles. The stopping potential V₀ is determined by the frequency f through the equation eV₀ = hf - ₀ , indicating equal stopping potentials imply equal frequencies. From the graph, curves a and b share the same stopping potential, so f_a = f_b . Curves c and d share a more negative stopping potential, so f_c = f_d and f_c > f_a . The saturation current is proportional to intensity I . Curve b has hi

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