MHT CET202526 Apr 2025Morning ShiftPhysicsDual Nature of MatterActual
The wavelength ' ' of a photon and the de-Broglie wavelength of an electron have same value. the ratio of kinetic energy of the electron to the energy of a photon is ( m = mass of electron, c = velocity of light, h = Planck's constant)
Options
- A2 m c h
- Bmc h
- Ch 2 m c
- Dh mc
Correct answer
C. h 2 m c
Step-by-step solution
For an electron and photon with equal wavelengths _e = _ ph = , the de Broglie relation gives the electron's momentum as p_e = h/ . The kinetic energy of the electron is KE_e = p_e^2 / (2m) = h^2 / (2m ^2) . The photon energy is E_ ph = hc/ . The ratio of kinetic energies simplifies to: KE_e E_ ph = h^2 2m ^2 hc = h 2m c This corresponds to option C .