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MHT CET202523 Apr 2025Evening ShiftPhysicsDual Nature of MatterActual

Graph shows variation of stopping potential with frequency of incident radiation on a metal plate. The value of Planck's constant is [ e = charge on photoelectron]

Options

  1. Ae (V₂-V₁ ) v₁ v₂
  2. Be V₁ V₂ (V_ 2- V₁ )
  3. Ce (V₂-V₁ ) (V_ 2- V₁ )
  4. De (V₁ V₂ ) V₁ V₂

Correct answer

C. e (V₂-V₁ ) (V_ 2- V₁ )

Step-by-step solution

The photoelectric effect follows Einstein's photoelectric equation : h = + K_ max , where h is Planck's constant, is the frequency of incident radiation, is the work function, and K_ max is the maximum kinetic energy. Since K_ max = eV_s where e is the electronic charge, substitution gives: h = + eV_s . Solving for V_s yields the linear relation: V_s = h e - e . This corresponds to a straight line with slope m = h/e . From the graph, the slope is calculated using two points: m = (V₂ - V₁)/( ₂ - ₁) . Equating the ex

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