When a light of wavelength falls on the emitter of a photocell, maximum speed of emitted photoelectrons is V. If the incident wavelength is changed to 2 / 3 , maximum speed of emitted photoelectrons will be

Step-by-step solution

The maximum kinetic energy of photoelectrons in the photoelectric effect is given by K_ = 1 2 mV^2 = hc - , where h is Planck’s constant, c is the speed of light, is the wavelength of incident light, and is the work function of the material. For incident wavelength producing maximum speed V : 1 2 mV^2 = hc - For incident wavelength 2 3 producing maximum speed V' : 1 2 m(V')^2 = hc 2 3 - = 3hc 2 - Assuming negligible work function ( = 0 ) to focus on the relationship: 1 2 mV^2 = hc 1 2 m(V')^2 = 3hc 2 Dividing these