An electron accelerated by a potential difference 'V' has de-Broglie wavelength ' '. If the electron is accelerated by a potential difference ' 9 V ', its de-Broglie wavelength will be

Step-by-step solution

The de Broglie wavelength of an electron accelerated through a potential difference V is given by = h 2meV where h is Planck’s constant, m is the electron mass, and e is the electron charge. This implies is inversely proportional to V , so 1 V and thus = C V where C = h 2me . For a potential difference of 9V , the corresponding wavelength ' satisfies ' = C 9V = C 3 V = 3 . Final Answer: 3