The maximum velocity of the photoelectrons emitted by a metal surface is 9 10^5 ~m / s . The value of ratio of charge (e) to mass (m) of the photoelectron is 1.8 10¹¹ C / kg . The value of stopping potential in volt is

Step-by-step solution

The maximum kinetic energy of photoelectrons is given by KE_ max = 1 2 mv_ max ^2 and also by KE_ max = eV_s , where m is the mass of the electron, v_ max is the maximum velocity, e is the charge of the electron, and V_s is the stopping potential. Combining these equations provides 1 2 mv_ max ^2 = eV_s . Solving for V_s yields V_s = 1 2 m e v_ max ^2 . Given e m = 1.8 10¹¹ , C/kg , it follows that m e = 1 1.8 10¹¹ , kg/C . Substituting this and v_ max = 9 10⁵ , m/s into the expression for V_s gives V_s = 1 2 1 1.8