MHT CET202416 May 2024Evening ShiftPhysicsDual Nature of MatterActual
Kinetic energy of a proton is equal to energy E of a photon. Let ' ₁ ' be the de-Broglie wavelength of proton and ' ₂ ' be the wavelength of photon. If ( ₁ ₂ ) E ^ n then the value of ' n ' is
Options
- A1
- B2
- C5
- D0.5
Correct answer
D. 0.5
Step-by-step solution
If E is the kinetic energy of the proton, then E= p^2 2 m where p is the momentum and m is the mass of proton p = 2 mE ₁= h p = h 2 mE Similarly, for a photon, E= h c ₂ aligned & ₂= h c E & ₁ ₂ = h 2 m E E h c = 1 c E 2 m & & ₁ ₂ E^ 1 / 2 n=0.5 aligned