MHT CET202416 May 2024Morning ShiftPhysicsDual Nature of MatterActual
The figure shows the variation of photocurrent with anode potential for four different radiations. Let I _ a , I _ b , I _ c and I _ d be the intensities for the curves a, b, c and d respectively [f_a, f_b, f_c . and f_d are frequencies respectively]
Options
- Af_a=f_b f_c f_d and I_a=I_b I_c I_d
- Bf _ a f _ b f _ c = f _ d and I _ a = I _ b I _ c ^ I _ d
- Cf _ a = f _ b = f _ c = f _ d and I _ a I _ b I _ c I _ d
- Df_a f_b f_c f_d and I_a=I_b=I_c=I_d
Correct answer
C. f _ a = f _ b = f _ c = f _ d and I _ a I _ b I _ c I _ d
Step-by-step solution
Since the stopping potential is same, they all have same frequency i.e., f_a=f_b=f_c=f_d From figure Photocurrent is highest for d followed by c, b and a. I _ a I _ b I _ c I _ d