MHT CET202410 May 2024Evening ShiftPhysicsDual Nature of MatterActual
Radius of first orbit in H -atom is ' a ₀ ' Then, de-Broglie wavelength of electron in the third orbit is
Options
- A3 a ₀
- B6 a ₀
- C9 a ₀
- D12 a ₀
Correct answer
B. 6 a ₀
Step-by-step solution
aligned & Radius for n ^ th orbit, r _ n = a ₀ n ^2 & For third orbit, & r ₃= a ₀ 3^2 & =9 a ₀ & Also, mvr = nh 2 & mv = nh 2 r = 3 ~h 2 9 a ₀ & = h mv = h 3 ~h 2 9 a ₀=6 a ₀ aligned