MHT CET20249 May 2024Morning ShiftPhysicsDual Nature of MatterActual
Two identical photocathodes receive light of frequencies ' n ₁ ' and ' n ₂ '. If the velocities of the emitted photoelectrons of mass ' m ' are ' V₁ ' and ' V ₂ ' respectively, then ( h = Planck's constant )
Options
- AV ₁+ V ₂= [ 2 ~h ~m ( n ₁+ n ₂ ) ]^ 1 / 2
- BV ₁- V ₂= [ 2 ~h ~m ( n ₁- n ₂ ) ]^ 1 / 2
- CV ₁^2+ V ₂^2= 2 ~h ~m ( n ₁+ n ₂ )
- DV ₁^2- V ₂^2= 2 ~h ~m ( n ₁- n ₂ )
Correct answer
D. V ₁^2- V ₂^2= 2 ~h ~m ( n ₁- n ₂ )
Step-by-step solution
aligned & K.E. .₁=h n₁- & K.E. 2= hn ₂- & K.E. 1 -K.E. 2= hn ₁- hn ₂ & ~m ( ~V ₁^2- V ₂ ₂ ) 2 = h ( n ₁- n ₂ ) & V ₁^2- V ^2 ₂=2 ~h ( n ₁- n ₂ ) m aligned