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MHT CET202313 May 2023Morning ShiftPhysicsDual Nature of MatterActual

When a light of wavelength 300 ~nm fall on a photoelectric emitter, photo electrons are emitted. For another emitter light of wavelength 600 ~nm is just sufficient for liberating photoelectrons. The ratio of the work function of the two emitters is

Options

  1. A1: 2
  2. B2: 1
  3. C4: 1
  4. D1: 4

Correct answer

B. 2: 1

Step-by-step solution

Work function ₀= hc ₀ aligned ₀ & 1 ₀ _ 0₁ _ 0₂ & = _ 0₂ _ 0₁ = 600 300 = 2 1 aligned

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