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MHT CET202312 May 2023Evening ShiftPhysicsDual Nature of MatterActual

Graph shows the variation of de-Broglie wavelength ( ) versus 1 V where ' V ' is the accelerating potential for four particles A, B, C, D carrying same charge but of masses m ₁, ~m ₂ , m ₃, ~m ₄ . Which on represents a particle of largest mass?

Options

  1. Am ₁
  2. Bm ₂
  3. Cm ₃
  4. Dm ₄

Correct answer

A. m ₁

Step-by-step solution

de Broglie wayelength = h p = h 2 mqv v = h 2 mq ( 1 v ) = 1 2 mq Slope of the graph = 1 2 mq The slope will be maximum for minimum mass. m ₄ is minimum and m ₁ will be minimum.

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