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MHT CET20227 Aug 2022Evening ShiftPhysicsDual Nature of MatterActual

Energy of photon whose frequency is 10¹² MHz is [Planck's constant, h =6.63 10⁻³⁴ Js , e =1.6 10⁻¹⁹ C ]

Options

  1. A4.14 10^3 keV
  2. B4.14 10^2 eV
  3. C4.14 10^3 MeV
  4. D4.14 10^3 eV

Correct answer

D. 4.14 10^3 eV

Step-by-step solution

Using plank energy quanta vs frequency relation: E(e V)= h v e = 6.63 10⁻³⁴ 10¹² 10^6 1.6 10⁻¹⁹ =4.14 10^3 eV

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