MHT CET20227 Aug 2022Morning ShiftPhysicsDual Nature of MatterActual
An electron of mass ' m ' and a photon have same energy E . The ratio of the de-Broglie wavelengths associated with them is (c = velocity of light in air)
Options
- A[ E 2 M ]^ 1 2
- B1 c [ E 2 ~m ]^ 1 2
- Cc (2 mE )^ 1 2
- D1 c [ 2 ~m E ]^ 1 2
Correct answer
B. 1 c [ E 2 ~m ]^ 1 2
Step-by-step solution
De-broglie wavelength For an electron, _ e = h 2 mE For photon, E = pc _ Photon = hc E _ e _ photon = h 2 mE E hc = ( E 2 ~m )^ 1 / 2 1 c