Light of two different frequencies whose photons have energies 1.3 eV and 2.8 eV respectively, successfully illuminate a metallic surface whose work function is 0.8 eV . The ratio of maximum speeds of emitted electrons will be

Step-by-step solution

For maximum speed of the photo electrons, 1 2 m v^2=E_ P - where =0.8 eV is the work function of the metal. Energy of photon E₁=1.3 eV 1 2 m v₁^2=1.3-0.8 eV Ratio of maximum speeds of the electrons can obtained by taking ratio of equation (1) and (2), v₁^2 v₂^2 = 0.5 2 = 1 4 Or, v₁ v₂ = 1 2