MHT CET202123 Sep 2021Evening ShiftPhysicsDual Nature of MatterActual
An electron of mass ' m ' and a photon have same energy ' E '. The ratio of de-Broglie wavelength of electron to the wavelength of photon is ( c = velocity of light )
Options
- Ac E m
- B1 c 2 m E
- C1 c E 2 m
- Dc m E
Correct answer
C. 1 c E 2 m
Step-by-step solution
If E is the kinetic energy of the electron, then aligned & E = p ^2 2 ~m ( p = momentum ) & p = 2 mE & de Broglie wavelength of electron & _ e = 1 2 mE & Energy of photon, E = hc _ p = hc E & _ e _ p = h 2 mE E hc = 1 c E 2 ~m aligned