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MHT CET202122 Sep 2021Morning ShiftPhysicsDual Nature of MatterActual

Kinetic energy of a proton is equal to energy ' E ' of a photon. Let ' ₁ ' be the de-Broglie wavelength of proton and ' ₂ ' is the wavelength of photon. If ₁ ₂ E ^ n , then the value of ' n ' is

Options

  1. A1 2
  2. B1 4
  3. C2
  4. D4

Correct answer

A. 1 2

Step-by-step solution

If E is the kinetic energy of the proton, then E= p^2 2 m where p is the momentum and m is the mass of proton p = 2 mE ₁= h p = h 2 mE For photon, E = hc ₂ ₂= hc E aligned & ₁ ₂ = h 2 mE E hc = 1 c E 2 ~m & ₁ ₂ E ^ 1 / 2 n = 1 2 aligned

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