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MHT CET202121 Sep 2021Evening ShiftPhysicsDual Nature of MatterActual

A proton and alpha particle are accelerated through the same potential difference. The ratio of the de-Broglie wavelength of proton to that of alpha will be (mass of alpha particle is four times mass of proton.)

Options

  1. A1: 2
  2. B2 2 : 1
  3. C1: 1
  4. D2: 1

Correct answer

B. 2 2 : 1

Step-by-step solution

De-Broglie wavelength is given by = h 2 mqV If ₁ and ₂ are de-Broglie wavelengths of proton and alpha particle then ₁ ₂ = m ₂ q ₂ ~m ₁ q ₁ = 4 2 = 8 =2 2

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